3[(2c)-4-(-c)+3]=2c+4

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Solution for 3[(2c)-4-(-c)+3]=2c+4 equation:


Simplifying
3[(2c) + -4 + -1(-1c) + 3] = 2c + 4

Remove parenthesis around (-1c)
3[(2c) + -4 + -1 * -1c + 3] = 2c + 4

Multiply -1 * -1
3[(2c) + -4 + 1c + 3] = 2c + 4

Reorder the terms:
3[-4 + 3 + (2c) + 1c] = 2c + 4

Combine like terms: -4 + 3 = -1
3[-1 + (2c) + 1c] = 2c + 4

Combine like terms: (2c) + 1c = 3c
3[-1 + 3c] = 2c + 4
[-1 * 3 + 3c * 3] = 2c + 4
[-3 + 9c] = 2c + 4

Reorder the terms:
-3 + 9c = 4 + 2c

Solving
-3 + 9c = 4 + 2c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2c' to each side of the equation.
-3 + 9c + -2c = 4 + 2c + -2c

Combine like terms: 9c + -2c = 7c
-3 + 7c = 4 + 2c + -2c

Combine like terms: 2c + -2c = 0
-3 + 7c = 4 + 0
-3 + 7c = 4

Add '3' to each side of the equation.
-3 + 3 + 7c = 4 + 3

Combine like terms: -3 + 3 = 0
0 + 7c = 4 + 3
7c = 4 + 3

Combine like terms: 4 + 3 = 7
7c = 7

Divide each side by '7'.
c = 1

Simplifying
c = 1

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